Debug School

rakesh kumar
rakesh kumar

Posted on

Php Programing Solution

1.solution
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2.because print statement does not take multiple argument.
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3.echo statement does not return any value. It will generate an error if you try to display its return value
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4.print returns a value, which is always 1.
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5.Hello world using echo
Hello world using ECHO
Hello world using EcHo
6.
Notice: Undefined variable: ColoR in D:\xampp\htdocs\program\p2.php on line 8
My car is
My dog is black
Notice: Undefined variable: COLOR in D:\xampp\htdocs\program\p2.php on line 10
My Phone is
7.

Parse error: syntax error, unexpected '4' (T_LNUMBER), expecting variable (T_VARIABLE)
 or '$' in C:\wamp\www\variableinvalid.php on line 2
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8.

Local variable declared inside the function is: 45 
?>
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9.

Web development language: PHP
Notice: Undefined variable: lang in D:\xampp\htdocs\program\p3.php on line 28
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10.

Variable inside the function: Sanaya Sharma
Variable outside the function: Sanaya Sharma
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11.

Notice: Undefined variable: name in D:\xampp\htdocs\program\p3.php on line 6
Variable inside the function:
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12.

Sum of global variables is: 18
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13.
If two variables, local and global, have the same name, then the local variable has higher priority than the global variable inside the function.

Value of x: 7
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14.

Static: 4
Non-static: 7
Static: 5
Non-static: 7
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