how to extract keys from list
how to extract values from list
how to extract list from grouped list of dictionary
how to extract list from grouped dictionary of list
input
numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9]
output
Another output
how to extract all first key's value in list from grouped list of dictionary
input
list_of_dicts = [
{"name": "Alice", "age": 25},
{"name": "Bob", "age": 30},
{"name": "Charlie", "age": 22}
]
output
['Alice', 'Bob', 'Charlie']
how to create grouped list of dictionary from bigger single list
how to create grouped dictionary of dictionary from bigger single list
input
numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9]
output
{'odd': {1: 1, 3: 3, 5: 5, 7: 7, 9: 9}, 'even': {2: 2, 4: 4, 6: 6, 8: 8}}
how to extract all values in in different list from grouped list of dictionary
input
grouped_dict = {
"group1": [1, 2, 3],
"group2": [4, 5, 6],
"group3": [7, 8, 9]
}
output
how to extract all keys in list from grouped list of dictionary
input
grouped_dict = {
"group1": [1, 2, 3],
"group2": [4, 5, 6],
"group3": [7, 8, 9]
}
output
how to extract list from grouped dictionary of list
how to extract all 2nd element from grouped dictionary of list
input
grouped_dict = {
"group1": [1, 2, 3],
"group2": [4, 5, 6],
"group3": [7, 8, 9]
}
output
[2, 5, 8]
how to extract list from group of list
how to extract all 2nd element from grouped list of list
input
data_list = [
[1, 2, 3],
[4, 5, 6],
[7, 8, 9]
]
output
[2, 5, 8]
how to extract all first keys in list from grouped dictionary of list
input
list_of_dicts = [
{"name": "Alice", "age": 25},
{"name": "Bob", "age": 30},
{"name": "Charlie", "age": 22}
]
output
['name', 'name', 'name']
extract all keys
['name', 'age', 'name', 'age', 'name', 'age']
how to extract all value in single list from grouped list of dictionary
input
grouped_dict = {
"group1": [1, 2, 3],
"group2": [4, 5, 6],
"group3": [7, 8, 9]
}
output
[1, 2, 3, 4, 5, 6, 7, 8, 9]
how to extract all value with group name in single list from grouped list of dictionary
input
grouped_dict = {
"group1": [1, 2, 3],
"group2": [4, 5, 6],
"group3": [7, 8, 9]
}
output
[('group1', 1), ('group2', 4), ('group3', 7)]
how to extract all values in single list from grouped dictionary of dictionaries
input
dict_of_dicts = {
"group1": {"name": "Alice", "age": 25},
"group2": {"name": "Bob", "age": 30},
"group3": {"name": "Charlie", "age": 22}
}
output
['Alice', 25, 'Bob', 30, 'Charlie', 22]
how to extract all values along with their corresponding key names in groupwiswe from a dictionary of dictionaries
input
dict_of_dicts = {
"group1": {"name": "Alice", "age": 25},
"group2": {"name": "Bob", "age": 30},
"group3": {"name": "Charlie", "age": 22}
}
output
[('group1', 'name', 'Alice'),
('group1', 'age', 25),
('group2', 'name', 'Bob'),
('group2', 'age', 30),
('group3', 'name', 'Charlie'),
('group3', 'age', 22)]
how to extract particular key value from dictionary of dictionaries
input
output
how to extract first dictionary from dictionary of dictionaries
input
dict_of_dicts = {
"group1": {"name": "Alice", "age": 25},
"group2": {"name": "Bob", "age": 30},
"group3": {"name": "Charlie", "age": 22}
}
output
{'name': 'Alice', 'age': 25}
how to extract first two dictionary from dictionary of dictionaries
input
dict_of_dicts = {
"group1": {"name": "Alice", "age": 25},
"group2": {"name": "Bob", "age": 30},
"group3": {"name": "Charlie", "age": 22}
}
output
[{'name': 'Alice', 'age': 25}, {'name': 'Bob', 'age': 30}]
how to extract all key and value in new dictionary from dictionary of dictionaries
input
dict_of_dicts = {
"group1": {"name": "Alice", "age": 25},
"group2": {"name": "Bob", "age": 30},
"group3": {"name": "Charlie", "age": 22}
}
output
{'Alice': 25, 'Bob': 30, 'Charlie': 22}
how to solve ValueError: arrays must all be same length
unsupported operand type(s) for +=: 'dict' and 'list
how to extract keys from dictionary
how to extract keys from list
data = {"name": "rakesh", "age": 33}
list=[]
for key in data.keys():
list.append(key)
print(list)
another way
data = {"name": "rakesh", "age": 33}
# Convert dictionary keys to a list
key_list = list(data.keys())
print(key_list)
how to extract values from list
data = {"name": "rakesh", "age": 33}
list=[]
for value in data.values():
list.append(value)
print(list)
another way
data = {"name": "rakesh", "age": 33}
# Convert dictionary keys to a list
value_list = list(data.values())
print(value_list)
output
how to create grouped list of dictionary from bigger single list
numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9]
# Initialize dictionaries for odd and even numbers
result_odd = {'odd': []}
result_even = {'even': []}
# Iterate through the numbers
for num in numbers:
if num % 2 == 0:
# Even numbers
result_even['even'].append(num)
else:
# Odd numbers
result_odd['odd'].append(num)
print(result_odd)
print(result_even)
output
==================or================
numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9]
# Initialize an empty dictionary
result_dict = {}
# Iterate through the numbers
for num in numbers:
key = 'even' if num % 2 == 0 else 'odd'
if key not in result_dict:
result_dict[key] = []
result_dict[key].append(num)
print(result_dict)
=======================or========================
# Initialize dictionaries for odd and even numbers
result_odd = {'odd': []}
result_even = {'even': []}
# Iterate through the numbers
for num in range(1,20):
if num % 2 == 0:
# Even numbers
result_even['even'].append(num)
else:
# Odd numbers
result_odd['odd'].append(num)
print(result_odd)
print(result_even)
how to create grouped dictionary of dictionary from bigger single list
numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9]
# Initialize an empty dictionary
result_dict = {'odd': {}, 'even': {}}
# Iterate through the numbers
for num in numbers:
if num % 2 == 0:
# Even numbers
result_dict['even'][num] = num
else:
# Odd numbers
result_dict['odd'][num] = num
print(result_dict)
=============================or=================
numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9]
# Initialize an empty dictionary
result_dict = {}
# Iterate through the numbers
for num in numbers:
key = 'even' if num % 2 == 0 else 'odd'
if key not in result_dict:
result_dict[key] = {}
result_dict[key][num]=num
print(result_dict)
output
{'odd': {1: 1, 3: 3, 5: 5, 7: 7, 9: 9}, 'even': {2: 2, 4: 4, 6: 6, 8: 8}}
how to create group dictionary of dictionary from list
numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9]
# Initialize an empty dictionary
result_dict = {'odd': [], 'even': []}
# Iterate through the numbers
for num in numbers:
if num % 2 == 0:
# Even numbers
result_dict['even'].append(num)
else:
# Odd numbers
result_dict['odd'].append(num)
print(result_dict)
how to extract list from grouped list of dictionary
how to extract all first key's value in list from grouped list of dictionary
list_of_dicts = [
{"name": "Alice", "age": 25},
{"name": "Bob", "age": 30},
{"name": "Charlie", "age": 22}
]
# Initialize an empty list
name_list = []
# Use a for loop to extract values for the key "name"
for d in list_of_dicts:
name_list.append(d["name"])
print(name_list)
another way
list_of_dicts = [
{"name": "Alice", "age": 25},
{"name": "Bob", "age": 30},
{"name": "Charlie", "age": 22}
]
# Extract values for the key "name" from each dictionary
name_list = [d["name"] for d in list_of_dicts]
print(name_list)
output
['Alice', 'Bob', 'Charlie']
how to extract all values in in different list from grouped list of dictionary
grouped_dict = {
"group1": [1, 2, 3],
"group2": [4, 5, 6],
"group3": [7, 8, 9]
}
# Initialize an empty list
element_list = []
# Use a for loop to extract the second element from each list in the values
for key,value in grouped_dict.items():
element_list.append(value)
print(element_list)
print(element_list[1])
output
how to extract all keys in list from grouped list of dictionary
grouped_dict = {
"group1": [1, 2, 3],
"group2": [4, 5, 6],
"group3": [7, 8, 9]
}
# Initialize an empty list
element_list = []
# Use a for loop to extract the second element from each list in the values
for key,value in grouped_dict.items():
element_list.append(key)
print(element_list)
print(element_list[1])
output
how to extract list from grouped dictionary of list
how to extract all 2nd element from grouped dictionary of list
grouped_dict = {
"group1": [1, 2, 3],
"group2": [4, 5, 6],
"group3": [7, 8, 9]
}
# Initialize an empty list
element_list = []
# Use a for loop to extract the second element from each list in the values
for lst in grouped_dict.values():
element_list.append(lst[1])
print(element_list)
output
[2, 5, 8]
Another way
grouped_dict = {
"group1": [1, 2, 3],
"group2": [4, 5, 6],
"group3": [7, 8, 9]
}
# Extract the second element from each list in the values
element_list = [lst[1] for lst in grouped_dict.values()]
print(element_list)
output
[2, 5, 8]
how to extract list from group of list
how to extract all 2nd element from grouped list of list
data_list = [
[1, 2, 3],
[4, 5, 6],
[7, 8, 9]
]
# Initialize an empty list
element_list = []
# Use a for loop to extract the second element from each inner list
for lst in data_list:
element_list.append(lst[1])
print(element_list)
output
[2, 5, 8]
how to extract all keys /colunm name value in list from grouped dictionary of list using list comprhension
list_of_dicts = [
{"name": "Alice", "age": 25},
{"name": "Bob", "age": 30},
{"name": "Charlie", "age": 22}
]
mylist = [key for data in list_of_dicts for key in data.keys()]
print(mylist)
output
['name', 'age', 'name', 'age', 'name', 'age']
how to extract all first keys in list from grouped dictionary of list
list_of_dicts = [
{"name": "Alice", "age": 25},
{"name": "Bob", "age": 30},
{"name": "Charlie", "age": 22}
]
# Initialize an empty list
key_list = []
# Use a for loop to extract keys from each dictionary
for d in list_of_dicts:
for key in d.keys():
key_list.append(key)
break # Only append the first key, assuming you want the first key
print(key_list)
output
['name', 'name', 'name']
how to extract all value in single list from grouped list of dictionary
grouped_dict = {
"group1": [1, 2, 3],
"group2": [4, 5, 6],
"group3": [7, 8, 9]
}
# Initialize an empty list
element_list = []
# Use a for loop to concatenate all elements from each list in the values
for lst in grouped_dict.values():
element_list += lst
print(element_list)
output
[1, 2, 3, 4, 5, 6, 7, 8, 9]
Another way
grouped_dict = {
"group1": [1, 2, 3],
"group2": [4, 5, 6],
"group3": [7, 8, 9]
}
# Initialize an empty list
element_list = []
# Use a for loop to extract all elements from each list in the values
for lst in grouped_dict.values():
element_list.extend(lst)
print(element_list)
output
[1, 2, 3, 4, 5, 6, 7, 8, 9]
how to extract all value with group name in single list from grouped list of dictionary
grouped_dict = {
"group1": [1, 2, 3],
"group2": [4, 5, 6],
"group3": [7, 8, 9]
}
# Initialize an empty list
element_list = []
# Use a for loop to extract the first element with the group name
for group, lst in grouped_dict.items():
element_list.append((group, lst[0]))
print(element_list)
output
[('group1', 1), ('group2', 4), ('group3', 7)]
how to extract all values in single list from grouped dictionary of dictionaries
dict_of_dicts = {
"group1": {"name": "Alice", "age": 25},
"group2": {"name": "Bob", "age": 30},
"group3": {"name": "Charlie", "age": 22}
}
# Initialize an empty list
all_values = []
# Use nested loops to extract all values
for inner_dict in dict_of_dicts.values():
for value in inner_dict.values():
all_values.append(value)
print(all_values)
['Alice', 25, 'Bob', 30, 'Charlie', 22]
how to extract all values along with their corresponding key names in groupwiswe from a dictionary of dictionaries
dict_of_dicts = {
"group1": {"name": "Alice", "age": 25},
"group2": {"name": "Bob", "age": 30},
"group3": {"name": "Charlie", "age": 22}
}
# Initialize an empty list
all_values_with_keys = []
# Use nested loops to extract all values with their corresponding key names
for outer_key, inner_dict in dict_of_dicts.items():
for inner_key, value in inner_dict.items():
all_values_with_keys.append((outer_key, inner_key, value))
print(all_values_with_keys)
Using list comprhension
mylist = [(group,key,value) for group,element in dict_of_dicts.items() for key,value in element.items()]
output
[('group1', 'name', 'Alice'),
('group1', 'age', 25),
('group2', 'name', 'Bob'),
('group2', 'age', 30),
('group3', 'name', 'Charlie'),
('group3', 'age', 22)]
how to extract particular key value from dictionary of dictionaries
dict_of_dicts = {
"group1": {"name": "Alice", "age": 25},
"group2": {"name": "Bob", "age": 30},
"group3": {"name": "Charlie", "age": 22}
}
# Initialize an empty list
first_name_values = []
# Use a for loop to iterate through the values associated with the key "name" in the first dictionary
for key, value in dict_of_dicts.items():
if key == "group1" and "name" in value:
first_name_values.append(value["name"])
print(first_name_values)
['Alice']
how to extract first dictionary from dictionary of dictionaries
dict_of_dicts = {
"group1": {"name": "Alice", "age": 25},
"group2": {"name": "Bob", "age": 30},
"group3": {"name": "Charlie", "age": 22}
}
# Initialize a variable to store the first dictionary
first_dict = None
# Use a for loop to iterate over the dictionaries
for key, value in dict_of_dicts.items():
first_dict = value
break # Exit the loop after the first iteration
print(first_dict)
{'name': 'Alice', 'age': 25}
how to extract first two dictionary from dictionary of dictionaries
dict_of_dicts = {
"group1": {"name": "Alice", "age": 25},
"group2": {"name": "Bob", "age": 30},
"group3": {"name": "Charlie", "age": 22}
}
# Initialize a variable to store the dictionaries
selected_dicts = []
# Use a for loop to iterate over the dictionaries
counter = 0
for value in dict_of_dicts.values():
selected_dicts.append(value)
counter += 1
if counter == 2:
break # Exit the loop after the second iteration
print(selected_dicts)
[{'name': 'Alice', 'age': 25}, {'name': 'Bob', 'age': 30}]
how to extract all key and value in new dictionary from dictionary of dictionaries
dict_of_dicts = {
"group1": {"name": "Alice", "age": 25},
"group2": {"name": "Bob", "age": 30},
"group3": {"name": "Charlie", "age": 22}
}
# Initialize an empty dictionary
name_age_dict = {}
# Use nested loops to extract values and construct a new dictionary
for inner_dict in dict_of_dicts.values():
name_value = inner_dict["name"]
age_value = inner_dict["age"]
name_age_dict[name_value] = age_value
print(name_age_dict)
output
{'Alice': 25, 'Bob': 30, 'Charlie': 22}
how to create grouped list of dictionary from dictionary of dictionary
dict_of_dicts = {
"group1": {"name": "Alice", "age": 25,"sub":"phy"},
"group2": {"name": "Bob", "age": 30,"sub":"che"},
"group3": {"name": "Charlie", "age": 22,"sub":"math"},
}
# Initialize an empty dictionary
name_age_dict = {}
newlist=[]
# Use nested loops to extract values and construct a new dictionary
for inner_dict in dict_of_dicts.values():
name_value = inner_dict["name"]
age_value = inner_dict["age"]
sub_value = inner_dict["sub"]
name_age_dict[name_value]=[]
name_age_dict[name_value].append(age_value)
name_age_dict[name_value].append(sub_value)
print(name_age_dict)
how to extract keys from dictionary
data = {"name": "rakesh", "age": 33}
key_list = []
for key, value in data.items():
key_list.append(key)
print(key_list)
how to solve ValueError: arrays must all be same length
import pandas as pd
numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9]
# Initialize an empty dictionary
result_dict = {'odd': [], 'even': []}
# Iterate through the numbers
for num in numbers:
if num % 2 == 0:
# Even numbers
result_dict['even'].append(num)
else:
# Odd numbers
result_dict['odd'].append(num)
print(result_dict)
# Convert the dictionary to a DataFrame
df = pd.DataFrame(result_dict)
# Display DataFrame
print(df)
solution
import pandas as pd
import numpy as np
numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9]
# Initialize an empty dictionary
result_dict = {'odd': [], 'even': []}
# Iterate through the numbers
for num in numbers:
if num % 2 == 0:
# Even numbers
result_dict['even'].append(num)
else:
# Odd numbers
result_dict['odd'].append(num)
print(result_dict)
# Determine the maximum length of the lists
max_len = max(len(result_dict['odd']), len(result_dict['even']))
# Pad lists to the same length with NaN
result_dict['odd'] += [np.nan] * (max_len - len(result_dict['odd']))
result_dict['even'] += [np.nan] * (max_len - len(result_dict['even']))
# Convert the dictionary to a DataFrame
df = pd.DataFrame(result_dict)
# Display DataFrame
print(df)
==============or============================
unsupported operand type(s) for +=: 'dict' and 'list
numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9]
import pandas as pd
import numpy as np
# Initialize an empty dictionary
result_dict = {'odd': {}, 'even': {}}
# Iterate through the numbers
for num in numbers:
if num % 2 == 0:
# Even numbers
result_dict['even'][num] = num
else:
# Odd numbers
result_dict['odd'][num] = num
print(result_dict)
# Determine the maximum length of the lists
max_len = max(len(result_dict['odd']), len(result_dict['even']))
# Pad lists to the same length with NaN
result_dict['odd'] += [np.nan] * (max_len - len(result_dict['odd']))
result_dict['even'] += [np.nan] * (max_len - len(result_dict['even']))
# Convert the dictionary to a DataFrame
df = pd.DataFrame(result_dict)
# Display DataFrame
print(df)
solution
import pandas as pd
import numpy as np
numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9]
# Initialize an empty dictionary
result_dict = {'odd': {}, 'even': {}}
# Iterate through the numbers
for num in numbers:
if num % 2 == 0:
# Even numbers
result_dict['even'][num] = num
else:
# Odd numbers
result_dict['odd'][num] = num
print(result_dict)
# Determine the maximum length of the dictionaries
max_len = max(len(result_dict['odd']), len(result_dict['even']))
# Add NaN to dictionaries to ensure the same length
result_dict['odd'].update({k: np.nan for k in range(len(result_dict['odd']), max_len)})
result_dict['even'].update({k: np.nan for k in range(len(result_dict['even']), max_len)})
# Convert the dictionary to a DataFrame
df = pd.DataFrame(result_dict)
# Display DataFrame
print(df)
output
{'odd': {1: 1, 3: 3, 5: 5, 7: 7, 9: 9}, 'even': {2: 2, 4: 4, 6: 6, 8: 8}}
odd even
1 1.0 NaN
3 3.0 NaN
5 5.0 NaN
7 7.0 NaN
9 9.0 NaN
2 NaN 2.0
4 NaN NaN
6 NaN 6.0
8 NaN 8.0
Cheatsheet
create single or multiple empty list or dictionary inside empty list or dictionary
result_odd = {'odd': []}OR result_dict[key] = []inside forloop
result_dict = {'odd': {}, 'even': {}}
how to create empty list as value for key after getting key of dictionary while iterating
if key not in result_dict:
result_dict[key] = []
how to create empty dictionary as value for key after getting key of dictionary while iterating
if key not in result_dict:
result_dict[key] = {}
adding new element in list as value of key inside dictionary
result_dict[key].append(num)
adding new dictionary with key-value as value of key inside outer dictionary
result_dict['even'][num] = num
odd or even check in list comprehension
key = 'even' if num % 2 == 0 else 'odd'
all dictionary key of outer list is added to in single list
for d in list_of_dicts:
name_list.append(d["name"])
============or=================
all dictionary key of outer list is added to in single list using list comprehension
name_list = [d["name"] for d in list_of_dicts]
all dictionary value of outer dictionary is added to in single list
for key,value in grouped_dict.items():
element_list.append(value)
=============or==========
all dictionary value of outer dictionary is added to in single list using list comprehension
element_list = [value for key,value in grouped_dict.items()]
element_list = [key for key,value in grouped_dict.items()]
Adding all value of first element(list) in new list from dictionary
for lst in grouped_dict.values():
element_list.append(lst[1])
Adding all value of specific element(list) in new list from dictionary using list comprehension
element_list = [value for key,value in grouped_dict.items() if key=="group2"]
Adding all value of first element(list) in new list from dictionary using list comprehension
element_list = [lst[1] for lst in grouped_dict.values()]
combine two list
merged_list = list(set(list1 + list2))
how to combine all list value in single list of outer dictionary
for lst in grouped_dict.values():
element_list += lst
how to combine all list value in single list of outer dictionary
for lst in grouped_dict.values():
element_list.extend(lst)
how to grouping key and list first element of outer dictionary
for group, lst in grouped_dict.items():
element_list.append((group, lst[0]))
how to grouping key and key of inner dictionary,value of inner dictionary of outer dictionary
for outer_key, inner_dict in dict_of_dicts.items():
for inner_key, value in inner_dict.items():
all_values_with_keys.append((outer_key, inner_key, value))
how to grouping key and list first element of outer dictionary using list comprhension
element_list = [(group, lst[0]) for group, lst in grouped_dict.items()]
how to find maximum value from two list
max_len = max(len(result_dict['odd']), len(result_dict['even']))
how to add nan(null) in list
result_dict['odd'] += [np.nan] * (max_len - len(result_dict['odd']))
Question
create single or multiple empty list or dictionary inside empty list or dictionary
how to create empty list as value for key after getting key of dictionary while iterating
how to create empty dictionary that is value for key after getting key of dictionary while iterating
adding new element in list that is value of key inside dictionary
adding new dictionary with key-value that is value of key inside outer dictionary
odd or even check in list comprehension
all dictionary key of outer list is added to in single list using list comprehension
all dictionary value of outer dictionary is added to in single list
all dictionary value of outer dictionary is added to in single list using list comprehension
Adding all value of first element(list) in new list from dictionary
Adding all value of specific element(list) in new list from dictionary using list comprehension
Adding all value of first element(list) in new list from dictionary using list comprehension
combine two list
how to combine all list value in single list of outer dictionary
how to grouping key and list first element of outer dictionary
how to grouping key and key of inner dictionary,value of inner dictionary of outer dictionary
how to grouping key and list first element of outer dictionary using list comprhension
how to find maximum value from two list
how to add nan(null) in list
how to extract all keys /colunm name value in list from grouped dictionary of list using list comprhension
Solution
result_odd = {'odd': []}OR result_dict[key] = []inside forloop
result_dict = {'odd': {}, 'even': {}}
if key not in result_dict:
result_dict[key] = []
if key not in result_dict:
result_dict[key] = {}
result_dict[key].append(num)
result_dict['even'][num] = num
key = 'even' if num % 2 == 0 else 'odd'
name_list = [d["name"] for d in list_of_dicts]
element_list = [value for key,value in grouped_dict.items()]
for lst in grouped_dict.values():
element_list.append(lst[1])
element_list = [value for key,value in grouped_dict.items() if key=="group2"]
merged_list = list(set(list1 + list2))
for lst in grouped_dict.values():
element_list += lst
element_list.append((key, lst[0]))
for outer_key, inner_dict in dict_of_dicts.items():
for inner_key, value in inner_dict.items():
all_values_with_keys.append((outer_key, inner_key, value))
max_len = max(len(result_dict['odd']), len(result_dict['even']))
result_dict['odd'] += [np.nan] * (max_len - len(result_dict['odd']))
mylist = [key for data in list_of_dicts for key in data.keys()]
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